2x+3(-x^2-1)=-3x^2+2(x-1)-3(x+2)

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Solution for 2x+3(-x^2-1)=-3x^2+2(x-1)-3(x+2) equation: 



2x+3(-x^2-1)=-3x^2+2(x-1)-3(x+2)

We move all terms to the left:

2x+3(-x^2-1)-(-3x^2+2(x-1)-3(x+2))=0

We multiply parentheses

-3x^2-(-3x^2+2(x-1)-3(x+2))+2x-3=0



We calculate terms in parentheses: -(-3x^2+2(x-1)-3(x+2)), so:

-3x^2+2(x-1)-3(x+2)

We multiply parentheses

-3x^2+2x-3x-2-6

We add all the numbers together, and all the variables

-3x^2-1x-8

Back to the equation:

-(-3x^2-1x-8)



We get rid of parentheses

-3x^2+3x^2+1x+2x+8-3=0

We add all the numbers together, and all the variables

3x+5=0

We move all terms containing x to the left, all other terms to the right

3x=-5

x=-5/3

x=-1+2/3

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